The Seahawks have signed Jamal Adams to a four-year extension that makes him the NFL’s highest-paid safety. The deal has a maximum value of $72 million and includes $38 million guaranteed.
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| AFC Conference vs NFC Conference | |
| Type: Moneyline - Status: OPEN | |
| NFC Conference | -105 |
| AFC Conference | -115 |
| AFC Conference vs NFC Conference | |
| Type: Moneyline - Status: OPEN | |
| AFC Conference | -115 |
| NFC Conference | -105 |